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10 < –3x + 1
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Subtract both sides by 1. What you get?
\(10 - \color{blue}{1} < -3x + 1 - \color{blue}{1} \)
@unheard
Did I do it correctly?
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@ash2326
Yeah @unheard \(10 -1=9\) and there -1 and 1 canceled each other, good work!
Thanks :)
Now, divide both sides by 3
\(\cfrac{9}{\color{blue}{3}} < \cfrac{-3x}{\color{blue}{3}}\) Can you tell me now?
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@unheard sorry it is not complete yet.
Did I do it correctly @mathslover ?
Yes. Now divide both sides by -1, would the signs change or not?
Yes.
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Can you show me . Please
3 > -x?
Don't forget to opposite the sign of -x and 3 also as u r dividing by -1.
|dw:1364227507915:dw|
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