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What amount of heat is required to increase the temperature of 75.0 grams of gold from 150°C to 250°C
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\[Q=mc \Delta T=75g0.032\frac{ kal }{ g ^{o}C}(250^{o}C-150^{o}C )\]
\[m=mass=75g, c=specificheat=0.032\frac{ kal }{ g ^{o}C }, \Delta T=changeintemperature=T _{f}-T _{i}=250^{o}C-150^{o}C\]
T=240kal
Sorry, Q=240kal which is the answer
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