Help!!! Graph equation and tell whether it is linear
y= -x^2+1
there is a distinction between linear quadratic do on...
|dw:1364271688023:dw|
y= mx + b Ax^2+By + C = 0
o whats the y intercept?
you got that there
so the x^2 draw a table of values
it will be easier to understand such that if x was then , output of y -------------------------- 2 4 you can do the rest
Graphical form: simplifies to Text form: y=-x^2+1 simplifies to y+x^2-1=0 Cartoon (animation) form: For tutors: simplify_cartoon( y=-x^2+1 )
Unless you can make sense of that Ashley1998, much of that (what you found on algebra.com) is a bit cryptic and odd in my opinion. Also, it might be more than what you're looking for. Basically this is NOT linear equation because it's a quadratic. It graphs a curved parabola which is NOT a straight line. The graph can be found by plotting a bunch of points and drawing a curve through every point When x = 0, y is y = -x^2 + 1 y = -(0)^2 + 1 y = 0 + 1 y = 1 So one point is (0,1) When x = 1, y is y = -x^2 + 1 y = -(1)^2 + 1 y = -1 + 1 y = 0 When x = 2, y is y = -x^2 + 1 y = -(2)^2 + 1 y = -4 + 1 y = -3 Etc etc Do this for x values from x = -3 to x = 3 to get the table x y ---------------------- -3 -8 -2 -3 -1 0 0 1 1 0 2 -3 3 -8 Giving you the points (-3,-8), (-2, -3), (-1, 0), (0, 1), (1, 0), (2, -3), (3, -8)
So plot the following points on the xy axis to get |dw:1364272761993:dw|
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