Mathematics
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OpenStudy (anonymous):
Simplify the radical expression .. r7 + r3
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jhonyy9 (jhonyy9):
so what can you factorizing out ?
OpenStudy (anonymous):
I'm not familiar with factoring radicals so I have no idea
jhonyy9 (jhonyy9):
radical expression ???
where is the radical indice ?
OpenStudy (anonymous):
lol \[\sqrt{75} + \sqrt{3}\]
OpenStudy (anonymous):
I think that's what it is and what's a radical indice? o.o
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jhonyy9 (jhonyy9):
yes now from these result that there are squareroot of 75 0n2 of 3
so can you rewrite the radical expression in exponent form ?
OpenStudy (anonymous):
uhmm..... -confused-
jhonyy9 (jhonyy9):
so the squareroot has ane xponent form so
sqrt(7) = 7^(1/2)
jhonyy9 (jhonyy9):
sqrt(25) = ?
OpenStudy (anonymous):
Where did 7 and 25 come from? e.O
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jhonyy9 (jhonyy9):
just for example
OpenStudy (anonymous):
And I apologize, I just realized my question is stated incorrectly
jhonyy9 (jhonyy9):
this is right
can you answer my example ?
OpenStudy (anonymous):
square root of 25 is 5 if that's what you mean
jhonyy9 (jhonyy9):
yes
how can you rewriting 75 using 25 ?
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jhonyy9 (jhonyy9):
like product of
jhonyy9 (jhonyy9):
so 75=25*3
jhonyy9 (jhonyy9):
this mean that
sqrt75 = sqrt(25*3) = sqrt25 * sqrt3 = ?
jhonyy9 (jhonyy9):
= 5sqrt3
OpenStudy (anonymous):
\[5\sqrt{3} ?\]
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OpenStudy (anonymous):
oohh I see
jhonyy9 (jhonyy9):
and the result ?
OpenStudy (anonymous):
There's another step?? o:
jhonyy9 (jhonyy9):
no just assum these
OpenStudy (anonymous):
>.<
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jhonyy9 (jhonyy9):
sqrt75 + sqrt3 = 5sqrt3 +sqrt3 = ?
OpenStudy (anonymous):
\[\sqrt{3 + 5} \sqrt{5}\]
jhonyy9 (jhonyy9):
no no
OpenStudy (anonymous):
dang it
jhonyy9 (jhonyy9):
sqrt(x) +sqrt(x) = ?
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OpenStudy (anonymous):
x? I have no idea
jhonyy9 (jhonyy9):
this is just an example
OpenStudy (anonymous):
I know.. and I'm failing at it
jhonyy9 (jhonyy9):
so a+a= ?
OpenStudy (anonymous):
\[a ^{2}\] or a?
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jhonyy9 (jhonyy9):
no you have confused these all
jhonyy9 (jhonyy9):
1+1= ?
OpenStudy (anonymous):
lmaooo omg
OpenStudy (anonymous):
2
jhonyy9 (jhonyy9):
so than a+a= ?
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OpenStudy (anonymous):
2a....?
jhonyy9 (jhonyy9):
yes
hurry up
jhonyy9 (jhonyy9):
and now sqrta +sqrta = ?
OpenStudy (anonymous):
2sqrta?
jhonyy9 (jhonyy9):
yeahhh
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jhonyy9 (jhonyy9):
so than 5sqrt3 + sqr3 = ?
OpenStudy (anonymous):
\[6\sqrt{6}\] ... or \[6 \sqrt{3+3}\]
jhonyy9 (jhonyy9):
why ????
2sqrta + 3sqrta = ?
OpenStudy (anonymous):
xD I suck....! pffft uhmmm 5sqrta
jhonyy9 (jhonyy9):
yes so than
5sqrt3 + sqrt3 = ?
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OpenStudy (anonymous):
See... that confuses me... there's nothing in front of the sqrt3 so is it 1 or 0? and am I supposed to add the sqrt3's together or what?
jhonyy9 (jhonyy9):
yes
5sqrt3 + 1sqrt3 =
OpenStudy (anonymous):
6sqrt3 ?
jhonyy9 (jhonyy9):
yes so thia will be the right answer
jhonyy9 (jhonyy9):
ok ?
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OpenStudy (anonymous):
OMGEE THANK YOU ! ughhhhhh that took a lifetime, thank you so much for enduring this with me >.<
jhonyy9 (jhonyy9):
was my pleasure
good luck
bye