Establish the identity tan u cot u - cos^2u=sin^2u
can you express tan u in terms of sin u and cos u ?
Not really, I barely learned this today with a sub who couldn't teach..
learn the basic identities first then? do you know any trigonometric identity ?
for this Question, you'll need these, \(\huge \tan x=\dfrac{\sin x}{\cos x} \\ \huge \cot x=\dfrac{\cos x}{\sin x} \\ \huge \sin^2x+\cos^2x=1\)
So.. sinx/cosx * cosx/sinx - cos^2u=sin^2u?
yes, what gets cancelled out ?
sinx/cosx*cosx/sinx
what remains ?
-cos^2u=sin^2u
a/a =1 and nor 0, so after cancelling out, the '1' remains, so you have 1-cos^2 u on left, got this ?
no... :(
why ? what part is confusing you ?
a/a =1 and nor 0, so after cancelling out, the '1' remains, ^ this part
whats 2/2 =... ?
1
yes, infact anything/same thing = 1 so, |dw:1364421048687:dw| now got that^ ?
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