Use the quadratic formula to find any x-intercepts on the graph of the equation. y=4x^2-2x-5
what are you having trouble with on this?
@HawkCrimson
\[(-b \sqrt[\pm]{b ^{2}-4ac} )/2a\]
where ax^2 +bx + c
okay your first equation was right!
just plug in the values and work it out :)
Trying to do that now =l
so I got, \[2\pm \sqrt{-76} / -4 \] doesnt seem right?
u made a mistake in the square root and the -4
ill show u know
I got it further down to \[-2\pm 2\sqrt{38}/ -4 \]
\[b ^{2}-4ac\] (-2)^2 - 4(4)(-5) 4 -4(-20) 4+80 = 84
2a 2(4) 8 not -4
\[2\sqrt[\pm]{84}/8\]
understand?
yeah that makes sense, now it's factoring it down.
no, next u square root the 84
so u'll get 9.17
\(84=4\times 21\) so \(\sqrt{84}=\sqrt{4}\sqrt{21}=2\sqrt{21}\)
you get \[\frac{2\pm2\sqrt{21}}{8}=\frac{2(1\pm\sqrt{21})}{8}=\frac{1\pm\sqrt{21}}{4}\]
umm @satellite73 that is all fun and gud but this question isnt so complicated..
it is if you want to write your answer in simplest radical form if you want a decimal, then you use a calculator
well thanks i didnt know that :) though we dont need to do that ill keep that in mind thx :D
He did have the correct answer.
Use the quadratic formula to find any x-intercepts on the graph of the equation. y=4x^2-2x-5 ^ That didnt ask for it in the racinal form but ok xD
radical*
that is true, but that's how the instructor had the answer =) no biggie. it wasn't specific enough.
lol ok but on the record, i did most of the work XP
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