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Divide.
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\[\frac{ 3n ^{2}-n }{ n^2-1 } \div \frac{ n ^{2} }{ n+1 }\]
Can you factor?
Not sure how
Factor n out of 3n^2-n
n^2-1 is the difference of two squares
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(n-1)(n+1) ? I'm just guessing, I suck at factoring, makes my brain well up .-.
That is good.
Now factor n out of 3n^2-n
And you MUST master factoring. Do whatever it takes.
(n+1)(n-1) >.< and I'll try
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What did you get when you factored n out of 3n^2-n?
(n+1)(n-2)
When you multiply (n+1)(n-2) do you get 3n^2-n?
ooh no.... how would I do check that though, FOIL or something?
|dw:1364477792031:dw|
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