By how much does the mean of the data set below change if the outlier is removed? Round your answer to the nearest tenth, if necessary. 8, 6, 9, 12, 19, 7, 10, 8 (1 point) 0.5 0.6 1.3 2.4
@phi @satellite73 @amistre64 @saifoo.khan @kropot72
@sami-21 @electrokid
HELP ME SOMEBODY PLEASE
First, calulate the mean: m1= (8 + 6 + 9 + 12 + 19 + 7 + 10 + 8)/8. Then remove the outlier (19) Now calculate the mean again: m2= (8 + 6 + 9 + 12 + 7 + 10 + 8)/7. If you then calculate m1-m2, you've found the difference.
is it 0.6?
@ZeHanz
No, I've got another result. What results did you get for both means?
72 and 372
Both are wrong. m1 = (8 + 6 + 9 + 12 + 19 + 7 + 10 + 8)/8. So: add up all the number, then divide by 8. You may use your calculator!
79/8 @ZeHanz
=9.875 OK, just write it as a decimal number. The answer options are also.
What is your outcome of m2 = (8 + 6 + 9 + 12 + 7 + 10 + 8)/7 ?
60/7 @ZeHanz
yes, that is 8.5714... Now the difference is 9.875-8.5714
1.3 !!!! thanks for all your help
YW!
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