Mathematics
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OpenStudy (anonymous):
solve by factoring: x^2=14x-33
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OpenStudy (anonymous):
move everything to one side first
OpenStudy (anonymous):
14x-33-x^2?
OpenStudy (anonymous):
is equal to 0
so 14x-33-x^2=0
preferably we want x^2 to be positive, so multiply by -1 or move everythign to the otherside will give x^2-14x+33=0
OpenStudy (anonymous):
now, solving by factoring,
list all the factor couples of 33
OpenStudy (anonymous):
11
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OpenStudy (anonymous):
11x3
OpenStudy (anonymous):
factor pairs, multiple pairs, same thing
ex. [1,33], [3,11], etc
OpenStudy (anonymous):
there should be two more left, list them
OpenStudy (anonymous):
1x33
OpenStudy (anonymous):
i already listed that one,
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OpenStudy (anonymous):
thats it. 11x3 and 1x33
OpenStudy (anonymous):
nope
-1 *-33 =?
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
(x-11) (x-3)?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
well, almost, you forgot =0
OpenStudy (anonymous):
(x-11) (x-3)=0. thanks so much!
OpenStudy (anonymous):
not done yet
OpenStudy (anonymous):
oh?
OpenStudy (anonymous):
zero property of multiplication means that either (x-11) =0
or (x-3)=0
so basically just solve for x
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OpenStudy (anonymous):
so x will have 2 answers
OpenStudy (anonymous):
11, 3?
OpenStudy (anonymous):
x= 11, x =3
its an equation, thus the answer would be an equation
OpenStudy (anonymous):
but yes x is equal to 11 and 3
OpenStudy (anonymous):
ok. i dont have to put it in an equation. i just had to put the two x values. so thanks for helping :)
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OpenStudy (anonymous):
computer assignment?
OpenStudy (anonymous):
some teachers will be picky about how the answer is written
OpenStudy (anonymous):
yeah. and i know. i hate it but you helped a lot.
OpenStudy (anonymous):
no prob