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simplify: x^2+9x+8/x^2+10x+9
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what do you get when you factor x^2+9x+8
(x+1) (x+8)
and when you factor x^2+10x+9 you get ______
(x+1) (x+9)
So \[\Large \frac{x^2+9x+8}{x^2+10x+9}\] turns into \[\Large \frac{(x+1)(x+8)}{(x+1)(x+9)}\] The "x+1" terms cancel out (since they divide to 1) leaving you with \[\Large \frac{x+8}{x+9}\] which is your fully simplified final answer.
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yay thanks its right!!
you're welcome
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