Question

A sample of college student GPA's are as follows:
2.5, 3.2, 3.8, 3.5, 2.8, 4.0
Find the mean absolute deviation. (Round your answer to the nearest hundreth.)

Answer 1

\[\sum_{i=1}^{n}\frac{|x _{i}-\bar{x}|}{n}\]

Answer 2

what it that

Answer 3

step 1. find mean

Answer 4

mean = (sum of all values) / number of values

Answer 5

the average is 19.8

Answer 6

so 19.8/6=3.3

Answer 7

ok.. mean = 3.3

Answer 8

correct so now what do I do with the 3.3

Answer 9

the variance is 3.3 right

Answer 10

Now you need to take each data value and subtract the mean. Then find the absolute value of the result. The first calculation is:
2.5 - 3.3 = -0.8
|0.8| = 0.8
Can you do the other 5 calculations and then add the 6 results? That result is then divided by 6 to find the Mean Absolute Deviation.

Answer 11

ok so I got 0 as my next answer

Answer 12

ooh.. wait. I was explaining the standard deviation.. follow @kropot72's response

Answer 13

2. you subtract each number from the mean (i.e., from 3.3) and neglect the sign. then find the average of these values.

Answer 14

I got 0

Answer 15

Taking the second data value3.2:
3.2 - 3.3 = -0.1
|-0.1| = 0.1
Can you now calculate a result using the third data value 3.8?

Answer 16

where does 3.8 come from

Answer 17

idk what you mean

Answer 18

Look at your question. 3.8 is the third data value from the left hand side.

Answer 19

Can you subtract the mean (3.3) from 3.8:
3.8 - 3.3 = ?

Answer 20

0.5

Answer 21

ok so now what do I do

Answer 22

The value you have just found is already positive. Therefore we do not need to find its absolute value. We just record 0.5 for future use.
Taking the fourth value (3.5) just subtract 3.3 from it and record the result:
3.5 - 3.3 = ?

Answer 23

@mbrousseau34 Are you there?

Answer 24

yes

Answer 25

i got 00.6 as my answer

Answer 26

Not really. The answer is found from
\[\frac{0.8+0.1+0.5+0.2+0.5+0.7}{6}=?\]