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Algebra 20 Online
OpenStudy (anonymous):

the graph (1) is the graph of f(x)=2^x . describe the transformation of the blue function (2) and write the equation of the graph .

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Hint: If you are moving from red to blue, then you are moving 5 units to the right and 2 units up

OpenStudy (anonymous):

thanks:) what would the equation be ??

jimthompson5910 (jim_thompson5910):

the red graph is 2^x if you shift it 5 units to the right, then you replace x with (x-5) if you shift 3 units up, then you just add on +3 ------------------------------------------------------- So that means 2^x turns into 2^(x-5) + 3

jimthompson5910 (jim_thompson5910):

So if f(x) = 2^x (red graph) then g(x) = 2^(x-5) + 3 (blue graph)

OpenStudy (anonymous):

thank you sooooo much :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

maybe you can help me with the other similar questions

jimthompson5910 (jim_thompson5910):

sure, i can do a few more

OpenStudy (anonymous):

the red graph (1)is the graph of f(x)=log(x). describe the tranasformation of the blue function and write the equation of the graph.

jimthompson5910 (jim_thompson5910):

you are shifting the red graph 5 units to the right and 5 units up to get the blue graph

jimthompson5910 (jim_thompson5910):

So f(x)=log(x). turns into f(x)=log(x-5) + 5 using the same rules described above

jimthompson5910 (jim_thompson5910):

I meant to write g(x) = log(x-5) + 5

OpenStudy (anonymous):

and thats for the blue graph right ?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

red ----> blue start with red, go to blue

OpenStudy (anonymous):

okay :) oneeeee more question ! :)

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

same thing but diffrent graph

jimthompson5910 (jim_thompson5910):

you have to reflect over the x axis, then move it down 3 units

OpenStudy (anonymous):

okay and the equation for the blue graph ?

jimthompson5910 (jim_thompson5910):

the original is f(x) = log(x) you reflect it over the x axis to get y = -log(x) then you move it down 3 units to get y = -log(x) - 3 So the blue graph is g(x) = -log(x) - 3

OpenStudy (anonymous):

okay thanks again :)

jimthompson5910 (jim_thompson5910):

np

OpenStudy (anonymous):

do you know how to do the unit circle stuff

jimthompson5910 (jim_thompson5910):

what do you mean

OpenStudy (anonymous):

like this

jimthompson5910 (jim_thompson5910):

ok something like would be very helpful to have in your notes http://www.regentsprep.org/Regents/math/algtrig/ATT5/600px-Unit_circle_angles_svg.jpg

jimthompson5910 (jim_thompson5910):

hopefully the unit circle is somewhat familiar to you

OpenStudy (anonymous):

yeah i have it but i dont understand how to do it

jimthompson5910 (jim_thompson5910):

well any point that is on the unit circle is the point (x,y) where x = cos(theta) y = sin(theta) theta = angle

jimthompson5910 (jim_thompson5910):

so the point (1/2, sqrt(3)/2) means cos(60) = 1/2 sin(60) = sqrt(3)/2 since this point is at the place where the angle is 60 degrees

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