Question

please help

Answer 1

okay so first find f'(x)

Answer 2

of course you would need product rule to do that

Answer 3

once you have f'(x), set it equal to 0 and solve for x to find the critical number

Answer 4

x = 4/7.... this fraction will have a vertical asymptote there...

Answer 5

what I have been struggling with is that finding f(x)'

Answer 6

I know the step but derivative

Answer 7

oops... function, and the function is actually a fraction

\[f(x) = \frac{1}{(7x -4)^{6x}}\]

Answer 8

dont you use In to solve this?

Answer 9

so the critical point... is what makes the denominator zero...

as the function does not exist or is undefined at x = 4/7

Answer 10

x=4/7 is the answer?

Answer 11

@campbell_st

Answer 12

I'd believe so