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verify: (sinx+cosx)squared=1+sin(2x)
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Use foil first. on \[\large (\sin x + \cos x)^2\]
can you show me how to solve it from the right side?
Sure. First, how do you perform the FOIL method, in squaring a binomial?
(x+y)² = x² + 2xy + y² right?
yes, i got sin\[2^\]+cos\[2^\]+cos(x)sin(x)+sin(x)cos(x)
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Or, sin²x + cos²x + 2sinxcosx
according to the pathagorean identity you can combine the sine and cosine Squared to equal 1
so how do you get rid of the cosx?
Yeah, so you have 1 + 2sinxcosx Now, what's the formula for sin(a+b) ?
sinxcosy+cosxsiny
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That's right :) Now what's the formula for sin(2x) = sin(x+x) ?
thank you, I forgot about that identity
So you can do it from here?
yeah, thanks
No problem.
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