HELP!!!
Rewrite it without all the flips.
I am sorry I don't understand:(
\[\frac{ 3x ^{5} }{ 4y ^{3} }\times \frac{ 8y ^{2} }{ 9x ^{4} }\times \frac{ 15 }{ 16yx ^{3} }\]
OK
And now do I add them together or factor? @just.chris
Make it all times so that it just a matter of canceling out common factors without having to figure out which is the numerator or denominator. Its times to factor.
so factor
Ok, thanks
They were just trying to mess with your head with the divid and the -1 exponent.
@just.chris I can't seem to factor it :(
I did it by changing all the numbers to least common factors so the top looked like this on my scrap paper: \[\left( 3 \right)\times\left(2\times2\times2 \right)\times\left( 3 \times 5 \right) \times x ^{5}y ^{2}\] Then did the same kind of thing for the bottom and cancelled out common factors.
Ok let me try then:(
Would A be the correct answer? @just.chris
Can you send show me what you came out with for the bottom?
For the bottom I got 4x^32 y^4
In the equation I cleaned up to make everything multiplication the denominator is: \[4y ^{3}\times9x ^{4}\times16yx ^{3}\] to multiply the variables add the exponents \[y ^{3} \times y =y ^{4}\]
@just.chris ok then y is y^4
x is x^7
Yes
And you multiply the numbers. Or you can factor to least common factors. Then just cancel things out of the top, which I did in one of the above replies, from the bottom, which you are well on your way to finishing now, to simplify.
@just.chris I can't seem to get the right answer :(
OK. forget about the numbers completely, just for the moment, and simplify the bottom for the variables only, x to the what times y to the what?
x^7 times y^3
Oops! x^7 times y^4. Did you miss a y or not understand?
I missed it :(
Sorry!!!
Good. So now do the numbers only, you can multiple them all together or give me least common factors for each grouped in parans like I did for the top.
(3)×(2×2×2)×(3×5)
(2 x 2) (3 x 3) and (4 x 4)
for the botom
Thats right you'll need to further reduce the 4's when you start canceling out but that's right. And it is 2 x 2 x 3 x 3 x 4 x 4, because its all multiplication. Can you put the top from above over what you've just done for the bottom and start cancelling now?
I got 10/16
You can factor 2 out of the top and the bottom. You probably don't need to any more but you should also factor the variables.
then I would get 5/8
Yup. Do you want to do the variables too now?
ok
I already did the top above x^5y^2, you did the bottom so what do you get when you cancel these out?
for the bottom we get y^2 and x^2
Excellent, now put it all together and you get?
5/ 8y^2x^2
Yup. This was an exercise to test your "neatness" making sure you get the right things on the top and the right things on the bottom and were careful about the math. Very patient of you to keep at it.
Thank you so much!!! Thanks to you I think that I will be able to do these kinds of problems alone. THANK YOU for your patience!!! you are such a good teacher!!! :)
Many people on here are just trying to get answers done for them. You are trying to learn. I respect that. Thank you, too.
Join our real-time social learning platform and learn together with your friends!