2x + 1 greater than or equal to 5 or -3x > -9 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
i'll help u with it dont worry..
@jhatesmath ??
thanks!
before that please post in the equation form..
@jhatesmath
thats what im confused with i dont know where to even start
in your maths book is it writtn in words n this way? @jhatesmath
im home schooled so i have to do everything on the computer i dont have a book
ya whatever so wherever it was written was it in words?
no
oh ok then its fynn. now i think your equation must be \[2x+1\ge5\] subtracting 1 from boh sides.. so wat do u get?
@jhatesmath ??
2x greater than or equal to 2
no 2xgreater dan =4 which makes x is greater dan=2 got it?
@jhatesmath ?? got it??
okay is that it for part 1 ?
yeah that's part 1.. now.. what will your solution set be?? i hope u know hat it is?? and can u reply a bit fast.. i'm sleepy..
x > 2 ?
yes the solution set is \[{x:x \ge2;x \in R}\]
got it?? @jhatesmath ??3
yeah what about part 2 ?
okay... \[-3x >-9\] so now dividing both sides by -1 wat do u get.. reply a bit fast..
@jhatesmath ??
neways.. dividing by -1 v get... \[3x <9\] bcuz its a rule that when u divide both sides by a -ive no the inequality sign changes... \[x=3\] so ther's ur answer!
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