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Chemistry 12 Online
OpenStudy (anonymous):

Describe possible way(s) to shift the equilibrium to the right for the following reaction: 2AB (s) arrow 2A (s) + B2(g). Justify your answer. ΔH = +298 kJ (Points : 5)

OpenStudy (anonymous):

Well, what causes shifts in equilibrium?

OpenStudy (anonymous):

Increases or decreases in reactants or products

OpenStudy (anonymous):

Okay, good. If there is a disturbance which favors the Reactants, which way does equilibrium shift? If there is a disturbance which favors the Products, which way does equilibrium shift? Once you answer these questions, you will be able to think of a few scenarios that will cause the equilibrium to shift to the right (favoring the products, the forward reaction). And as for justification, you already know why :)

OpenStudy (anonymous):

I there is a disturbance which favors reactants there will be a shift right, if thee is a disturbance in products it will shift left. I am not sure how to manipulate the equation to show those shifts

OpenStudy (anonymous):

Okay, so disturbances that favor the reactant will cause equilibrium to shift right. Define the term "Favors" and apply it to the reactants (left side).

OpenStudy (anonymous):

3AB(s)-->2A(s)+B2(g)

OpenStudy (anonymous):

In that case the equation would be unbalanced. You don't necessarily have to manipulate the equation (because it's given). I think you meant to increase the [concentration] of the reactant. In that case, if you increase the concentration of AB, the equilibrium would shift to the right. There are a few other ways to create a disturbance.

OpenStudy (anonymous):

Is the concentration in the parenthesis?

OpenStudy (anonymous):

Concentration as in 0.1 Molar, 2.00 Molar, 12.00 Molar

OpenStudy (anonymous):

I am sorry but I completely do not understand.. I didn't get the mole thing at all

OpenStudy (anonymous):

In theory if you increased the molarity of the reactants (favoring the reactant side), the equilibrium would have to shift to the right in order to restore balance.

OpenStudy (anonymous):

right I understood that part I just do not know where I would write an increase in the mole

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