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Mathematics 18 Online
OpenStudy (anonymous):

HELP PLEASE!

OpenStudy (anonymous):

OpenStudy (anonymous):

Whats the LCD of x, x+1 @RH ?

OpenStudy (anonymous):

x(x+1) @SandeepReddy

OpenStudy (anonymous):

then whats the concise form of numerator?

OpenStudy (anonymous):

i mean if you want to write in a single p/q form. then what is it?

OpenStudy (anonymous):

1/x

OpenStudy (anonymous):

@SandeepReddy

OpenStudy (anonymous):

\[\frac{ 1 }{ x }-\frac{ x }{x+1 } = \frac{ (x+1)*1- x*x}{x(x+1) }=\frac{ (x+1)-x^2 }{ x(x+1) }\]

OpenStudy (anonymous):

Isn't it?

OpenStudy (anonymous):

@SandeepReddy this is for the numerator, right?

OpenStudy (anonymous):

YES! now you tell me whats going to be the denomenator?

OpenStudy (anonymous):

-x + 1/x + 1

OpenStudy (anonymous):

@SandeepReddy is it correct?

OpenStudy (anonymous):

\[\frac{ 2 }{ x+1}-\frac{ x-1 }{x }=\frac{ 2x-(x^2-1) }{ x(x+1) }\]

OpenStudy (anonymous):

So this is the denominator, right?

OpenStudy (anonymous):

So the final result is |dw:1364660741870:dw|

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