A plane is defined by the equation: x=4y+2z=16.
Find two vectors parallel to the plane.

Question

A plane is defined by the equation: x=4y+2z=16. 
Find two vectors parallel to the plane.

anonymous · Answer

do you know the rule of parallelism?

anonymous · Answer

nope

anonymous · Answer

Two vectors  and  are parallel if their cross product is zero, i.e., .u*v=0

anonymous · Answer

Okay do what do i do :S @SerikMB

anonymous · Answer

do you have exact answers?

anonymous · Answer

one of them may probable be y=-1/2x+2z

anonymous · Answer

Like what do i do to come up with that answer ?

anonymous · Answer

when two equations are parallel they have the same slopes

anonymous · Answer

as it says parallel the equation is linear so it's form is y=kx+b , but here instead of k it will be the slope

anonymous · Answer

then as vectors usually start at (0,0) point

anonymous · Answer

you can substitue it into the formula $$Y_{1}-Y _{2}=m(X _{1}-X _{2})$$

anonymous · Answer

where m is the slope

anonymous · Answer

given this equation:  x=4y+2z=16.

anonymous · Answer

yea it's just 3 dimensional

anonymous · Answer

im still not understanding this