Solve...

Question

Solve...

anonymous · Answer

attachment

anonymous · Answer

x = 5

x = 4

x = –1

None of the above

abb0t · Answer

Seeing that it came from a test, I don't think it would be ethical for me to give you the answer as it would be considered cheating.

anonymous · Answer

Just take the square both the sides first and tell me what did you get?

anonymous · Answer

2.45-1=2.23

tkhunny · Answer

FIRST, say $6x - 1 \ge 0$. leading to $x \ge 1/6$

SECOND, square both sides.

anonymous · Answer

You have taken square root there, I am saying to SQUARE both the sides...

anonymous · Answer

$$(\sqrt{6x-1})^2 = (\sqrt{5})^2$$

How can you solve this?

anonymous · Answer

Ah ok
36x-1=25

anonymous · Answer

It means I am really bad at teaching.. :)

anonymous · Answer

See, if I have $\sqrt{4x - y}$ then on square this only root will get cancelled.

$$(\sqrt{4x - y})^2 = 4x - y$$

Now again try it..

anonymous · Answer

When you square a square root, they cancel each other out, so you would have 6x-1=5. Then, solve for x :D. Now, an important step is to check if x works by plugging it back in, because some of these problems may look like they have a solution;however have not solution at all.