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Mathematics 21 Online
OpenStudy (anonymous):

HELP PLEASE!

OpenStudy (anonymous):

OpenStudy (anonymous):

r u doing ur homework here?

jhonyy9 (jhonyy9):

so what is your opinion please ?

OpenStudy (anonymous):

It is from the study guide, not homework

OpenStudy (anonymous):

ok .but what do u thing about the answer?

OpenStudy (anonymous):

I was thinking that A would be correct?

OpenStudy (anonymous):

ok but ur proof?

OpenStudy (anonymous):

But I am not sure, since C is supposed to be the longest side, I assumed that XZ would be longer than AC. So I change my mind to C

OpenStudy (anonymous):

it's so easy just think a little and notice the information given

OpenStudy (anonymous):

hmmm... then XY < AB ?

OpenStudy (anonymous):

since B is larger than Y

OpenStudy (anonymous):

'cmon they are same as the given information in the shape

OpenStudy (anonymous):

XY=AB YZ=BC

OpenStudy (anonymous):

and B>A so ?

Directrix (directrix):

In Geometry, there is no getting around the theorems to help solve a problem, especially inequalities like this one. Consider the theorem: If two sides of one triangle are congruent to two sides of another triangle and the included angle of the first triangle is greater than the included angle of the second triangle, then the third side of the first triangle is greater than the third side of the second. The black and blue triangles satisfy the hypothesis of the theorem. Angle B is larger than angle Y which, according to the theorem, means that AC > XZ or, as written in the options, XZ < AC.

OpenStudy (anonymous):

Thank you

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