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Physics 22 Online
OpenStudy (yrelhan4):

A block on a rough inclined plane..... Question attached.

OpenStudy (yrelhan4):

OpenStudy (yrelhan4):

@Mashy

OpenStudy (yrelhan4):

@shubhamsrg @DLS

OpenStudy (dls):

Its easy.

OpenStudy (anonymous):

What the heck is that ? Sry i only understand english

OpenStudy (yrelhan4):

Ignore the hindi part. Its just the translation of the question.

OpenStudy (anonymous):

I ve got d ans.

OpenStudy (yrelhan4):

For the first question?

OpenStudy (anonymous):

yes

OpenStudy (yrelhan4):

Its a. Might me some minor mistake.

OpenStudy (anonymous):

Here Suppose the block has moved a distance x

OpenStudy (anonymous):

then at position x balance the forces i.e. mgsin(-) - umgcos(-) = 0 Integrate this from 0 to x

OpenStudy (anonymous):

u get the answer on simplification.

OpenStudy (anonymous):

Reply when done

OpenStudy (yrelhan4):

Well i get this sin(-)=mu*x^2/2*cos(-) Doesnt give me the required answer? @lordcyborg

OpenStudy (anonymous):

there is no m term on RHS

OpenStudy (anonymous):

and u missed an 'x' term on LHS

OpenStudy (yrelhan4):

There is. You see the coefficient of friction given is mu=mu(not)*x. Ah, so we are not balancing forces, we are conserving the work. I get it. But that still doesnt give me a ?

OpenStudy (anonymous):

hey man/woman................. on integrating u get mgsin(theta)*x=u.mgcos(theta)*(x^2)/2 Cut mg and 'x' on both sides.......... U get the answer........now try it fast

OpenStudy (yrelhan4):

Oh. But you cant balance forces for the body to stop right? You have to conserve the work done?

OpenStudy (yrelhan4):

When you balance forces, it means there is no acceleration. It doesnt necessarily mean that the body is at rest? And a man.

OpenStudy (anonymous):

lol.........Dont go too deep...........i'm balancing forces when body is at rest

OpenStudy (yrelhan4):

I dont think you can balance force for the body to be at rest.

OpenStudy (anonymous):

ya we cannot all times.........bt we can

OpenStudy (yrelhan4):

Why doesnt conservation of energy give me the answer?

OpenStudy (anonymous):

coz u can apply dt when there are conservative forces.......in this case friction is not acting as a conservative force..........Now dont make me bore

OpenStudy (yrelhan4):

You can leave if you are getting bored. You chose to answer my question. I didnt tell you to come here and help me. Thank you.

OpenStudy (anonymous):

C'mon man............I gave u the perfect(i suppose) reasons.........now go and sleep it 2:15 a.m.

OpenStudy (yrelhan4):

Yeah you did. Thank you.

OpenStudy (shubhamsrg):

|dw:1364764688058:dw| a = gsin@ - u0 x gcos@ vdv = (gsin@ - u0 xgcos@)dx => 0 = gsin@ x - u0 gcos@ x^2/2 x=0 and x = 2tan@/u0

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