What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

y = –x – 1

y = –x + 5

y = x + 1

y = x + 5

Question

What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

y = –x – 1

y = –x + 5

y = x + 1

y = x + 5

anonymous · Answer

step 1) when two lines are perpendicular, the product of their slopes is "-1"
use this information and find the slope of the new line
m = ?

anonymous · Answer

@some_someone

anonymous · Answer

@electrokid  im not sure what m equals

anonymous · Answer

what is the slope of the given line $y=-x-3$

anonymous · Answer

1st, find the slope, m1, of y = –x – 3 by putting it in slope-intercept form. (That means solve for y) In this case its already in slope intercept form. 
Slope intercept form: y = mx + b

anonymous · Answer

m1 = -1
---------
The slope of lines perpendicular is the negative inverse of m1, = +1

anonymous · Answer

Use y = mx + b and the point to find b. 
3 = (1)(2) + b 
3 = 2 + b
1 = b

anonymous · Answer

y = x + 1 is thru (2 , 3) and perpendicular to y = –x – 3

anonymous · Answer

so @some_someone  is the answer c?

anonymous · Answer

Precisely :D

anonymous · Answer

thank you can you help me with the next answer please