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Mathematics 12 Online
OpenStudy (anonymous):

Solve for x and y (picture attached- ignore everything except the angle measurements and the 7)

OpenStudy (anonymous):

OpenStudy (anonymous):

Consider Cos 30 = 7/y and Sin 30 = x/y And knowing that sin 30 = 1/2 , and cos 30 = sqrt(3)/2, then you can find both x and y.

OpenStudy (anonymous):

i dont know the whole sin and cos stuff

OpenStudy (anonymous):

Remember soh cah toa. In a right triangle, for any of the angles that arent 90, say a sin a = opposite/hipotenuse cos a = adyacent/hipotenuse tan a = opposite/ adyacent In this case, for the 30° angle, opposite = x, adyacent = 7 and hipotenuse = y, so sin 30 = x/y and cos 30 = 7/y.

OpenStudy (anonymous):

i didn't learn soh cah toa

OpenStudy (anonymous):

Well, is good to learn that, is the way for solve this kind of problem. By the way the answers for your queston are \[x = 7\sqrt3/3, y = 14\sqrt3/3\] Just consider this famous triangle and make \[7=a*\sqrt3\].

OpenStudy (anonymous):

OpenStudy (anonymous):

is sqr root of 3 divided by 3 simplified?

OpenStudy (anonymous):

Actually, \[7/\sqrt3 =(7\sqrt3)/3 \] and \[14/\sqrt3 = (14\sqrt3)/3\] You can´t simplify anymore.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

You´re welcome.

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