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Mathematics 18 Online
OpenStudy (anonymous):

Need help graphing exponential functions

OpenStudy (anonymous):

Y=(1/2)^2x

OpenStudy (anonymous):

i dont understand what part u specifically need help in do u want to kno how ti find intercepts, or if it is just to graph u can just plug in values

OpenStudy (anonymous):

I know how to find the intercept, it's (0,4) The other points I don't understand

OpenStudy (anonymous):

just plug in values in ur calculator

OpenStudy (anonymous):

1/2 life graphs are very common ull find a pattern

OpenStudy (anonymous):

When I plug the function in y= I only get the intersection

OpenStudy (anonymous):

-1..4 1..1/4 2..0.0625

geerky42 (geerky42):

\[\large y=(1/2)^{2x} = 4^{-x}\]

OpenStudy (anonymous):

I think half life expressions are more common in highschool textbooks

OpenStudy (anonymous):

it should look like this . . . . . . .

OpenStudy (anonymous):

Or (1/4)^x But I don't know how they got (0,1)

OpenStudy (anonymous):

Aside from (1/4)^x

geerky42 (geerky42):

\(\Huge\cdot\) \(\Huge\cdot\) \(\Huge\cdot\) \(\Huge\cdot\) \(\Huge\cdot\) \(\Huge\cdot\) (0,1) - \(4^{-0} = 4^0 = 1\)

geerky42 (geerky42):

-0 and 0 is same, it's just zero.

OpenStudy (anonymous):

(1/2 )^(2*0)=1/2^(0)=and we kno anything to power 0 is 1

geerky42 (geerky42):

except \(0^0\), lol.

OpenStudy (anonymous):

Okay so for y=(1/2)^x-2 How did they get (1,2)?

OpenStudy (anonymous):

god tht nightmare are u taking calculus II in uni?

geerky42 (geerky42):

x =1 so (1/2)^(1)-2 = (1/2)^-1 = 2

OpenStudy (anonymous):

It's terrible

OpenStudy (anonymous):

y=(1/2)^(1-2) = (1/2)^(-1) =2

OpenStudy (anonymous):

u flip denominator to make power positive

OpenStudy (anonymous):

That you both! I finally get it So simple....

geerky42 (geerky42):

Glad we helped.

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