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Mathematics 8 Online
OpenStudy (anonymous):

What is the product in simplest form? State any restrictions on the variable.

OpenStudy (anonymous):

OpenStudy (anonymous):

try factoring each term as much as possible.

OpenStudy (anonymous):

is it y + 2/y + 1 y+ 3, -1

OpenStudy (anonymous):

tomo is right factoring gives \[\frac{ y^2 }{ y-3} * \frac{ (y+2)(y+3) }{ y(y+1) }\] multiplying across gives \[\frac{ y^2(y+2)(y-3) }{ y(y-3)(y+1) }\] now cancel the (y-3)'s and one y from both the numerator and denominator this gives the final simplest form \[\frac{ y(y+2) }{ (y+1) }\] because division by zero is undefined (and x = -1 causes the denominator to equal 0) the domain must be restricted to \[(-\infty,-1) \cup (-1,\infty)\] (all real numbers except -1)

OpenStudy (anonymous):

oops. the first equation should say (y-3), not y+3

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