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Fluid leaks out of a bottle at the rate of ln(1+t)+cos(t+ sqrt(t)) milliliters per minute, where t is measured in minutes. if the bottle contains 375 ml of fluid at time t=0 min, how many ml of fluid are in the bottle at time t=60?
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You want \(F(60)\) Given: \[ F'(t) = \ln(1+t)+\cos(t+ \sqrt{t})\\ F(0) = 375 \] Just use the fundamental theorem of calculus: \[ \int_0^{60}\ln(1+t)+\cos(t+ \sqrt{t})dt = F(60) - 375 \]
Basically that formula comes from: \[ \int_a^b F'(t)dt = F(b) - F(a) \]
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