Question

limit as n approaches infinity
(-3)^n
--------
3^n *n*sqrtn

Answer 1

Surely this doesn't have a limit as it diverges?

Answer 2

It does actually. It's part of a series.

Answer 3

Oh, sorry, I was looking at (-3)^n by itself. :S

Answer 4

doesnt (-3)^n = (-1)^n 3^n ?

Answer 5

yes. I simplified it further to (-1)^n /(n^3/2)

Answer 6

you can absolute it, and compare to n^(-3/2) right?

Answer 7

What test is that?
Absoluting it that is.