Question

find the area of a rectangular object which has the length of 5 √8 feet and a with of 2 √ 5 feet

Answer 1

well area is

A = length x width

so you are multiplying radicals

\[A = 5\sqrt{8} \times 2\sqrt{5} = 5 \times 2 \times \sqrt{8} \times \sqrt{5} \]

all you need to do is simplify the product of the radicals.

Answer 2

how exactly do i do that?

Answer 3

use one of the rules for radicals.

\[\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}\]

Answer 4

im sorry but i still dont have a clue

Answer 5

ok... so

\[\sqrt{8} \times \sqrt{5} = \sqrt{8 \times 5} \]

so the area is

\[A = 5 \times 2 \times \sqrt{8 \times 5}\]

hope this helps.

Answer 6

yes it does thanks a bunch