Question

What is the mass of 5.80 × 10^23 atoms of silver (Ag)?

0.00893 g

0.00963 g

104 g

112 g

Answer 1

multiply it with avogadro's number (6.02 x 10^23)
then you'll have the amount of moles Ag
You can then use the molecular weight to calculate the mass

Answer 2

Sorry it's divide by avogadro's number not multiply xD

Answer 3

That would come to 0,963 moles Ag
Molecular weight of Ag = 107,8682
0,963 x 107,8682 = 103,9 grams

Answer 4

So the answer would be 104g

Answer 5

Ohh Okay. Thank you!