Question

Simplify the given expression: √-10 times √-8

Answer 1

sqrt(2*5)*sqrt(2*2*2)=sqrt(2*2*2*2*5)=2*2sqrt(5)=4sqrt(5)

Answer 2

wait wait is that a negative?

Answer 3

forget everything I said

Answer 4

Yes!

Answer 5

haha okay

Answer 6

and is there an i in the answer? like as in imaginary numbers

Answer 7

ye then it's goes like: i d0Nt KnoW

Answer 8

\[i \sqrt{10}\times i \sqrt{8}\]

Answer 9

\[i ^{2}\times \sqrt{80}\]

Answer 10

\[i ^{2}\times 4\sqrt{5}\]

Answer 11

\[-4\sqrt{5}\]

Answer 12

cblr did it correctly except you for the imaginary part
write sqrt(-10)*sqrt(-8) as i * sqrt(10)* i * sqrt(8)
or
i *i* sqrt(10)* sqrt(8)

now you can do cblrtopas idea
but you also have a i*i out front (which you know is equal to -1)

Answer 13

i=sqrt(-1) I think. So, i*sqrt(10)*i*sqrt(8) --> i^2*sqrt(80)=-4*sqrt(2)

Answer 14

the idea is break the numbers 10 and 8 into their factors, and pull out pairs of numbers from out of the square root.

Answer 15

I mean -4*sqrt(5)

Answer 16

My choices are:

A. -4√5
B. 4√5
C. 4i√5
D. -4i√5

Answer 17

D it up

Answer 18

Now help me with my problems

Answer 19

yeah i narrowed it down to A and D. i know it's negative, i just dont know if theres an i or not

Answer 20

No, it's A seriously

Answer 21

hahaha okay thanks

Answer 22

what subject are you working on?

Answer 23

It's A

Answer 24

It's my can; y'see....I'm just kidding have a good day sir.