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a plane is perpendicular to both [x,y,z]=[1,-10,8]+s[1,2,-1] and [x,y,z]=[2,5,-5]+t[2,1,-3] and contains the point P(-1,4,-2). Determine if the point A(7,10,16) is also on the plane.
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cross your direction vectors to get the normal; then apply the given point to it, then see of the questionable point fits the equation
i always tend to misread perp and parallel
unless the direction vectors are scalars of one another, i dont see a plane being perp to both
|dw:1365031746530:dw|
now if its parallel to both lines, then the direction vectors can be part of the plane, and a normal can be determined by a cross
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