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Mathematics 8 Online
OpenStudy (meilendurcer):

If the hypotenuse is 41 inches, and one of the legs is 40 inches, what is the length of the other leg in inches?

OpenStudy (anonymous):

very much like the last one

OpenStudy (anonymous):

start with \[a^2+40^2=41^2\] then solve for \(a^2\) and then for \(a\)

OpenStudy (meilendurcer):

yeah.. thats the one i was looking at and got mixed up with..

OpenStudy (anonymous):

the other leg is 9 inches

OpenStudy (anonymous):

or you can go right to \[a=\sqrt{40^2-41^2}\]

OpenStudy (anonymous):

ah that is the one you have before, right?

OpenStudy (meilendurcer):

thanks but i am going the long way. 81?

OpenStudy (anonymous):

yes, 81 is \(a^2\)

OpenStudy (meilendurcer):

yeah it is

OpenStudy (anonymous):

and so this time \(a=9\)

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