Mathematics
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OpenStudy (anonymous):
Use half angle identities to find exact value:
tan Ө
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OpenStudy (anonymous):
Ө=22.5 degrees
OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
got sin and cosӨ, just stuck on tanӨ :O
hero (hero):
I'm kinda busy. Ask @hartnn
OpenStudy (anonymous):
@everyone!
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OpenStudy (aravindg):
hint
22.5*2 = 45
OpenStudy (aravindg):
now use tan 2 theta formula :)
OpenStudy (aravindg):
\[\large \tan 2 \theta=\dfrac{2\tan \theta}{1+\tan^2 \theta}\]
OpenStudy (aravindg):
you will get a quadratic in tan theta
OpenStudy (aravindg):
oops its 1-tan^2
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OpenStudy (anonymous):
isn't that double angle formula ?
OpenStudy (anonymous):
i want half angle :P
OpenStudy (aravindg):
I think this is enough ..you get a quadratic
hero (hero):
I agree. There should be an @everyone ping
OpenStudy (anonymous):
lol
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OpenStudy (anonymous):
umm but i want to see it in half angle!
OpenStudy (anonymous):
well..more like i need to see it in half angle lol
OpenStudy (aravindg):
theta =2ttheta/2
OpenStudy (aravindg):
infact I applied half angle here took 22.5 as half angle for 45
hartnn (hartnn):
\(\large \tan \theta=\dfrac{2\tan (\theta/2)}{1+\tan^2 (\theta/2)}\)
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OpenStudy (aravindg):
1-tan^2 theta/2 ?
OpenStudy (anonymous):
hold on..this is not the way i learn in class :|
hartnn (hartnn):
yeah, 1- ...
OpenStudy (aravindg):
:)
OpenStudy (anonymous):
what about cos or sin ?
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OpenStudy (aravindg):
you can use formula for cos 2 theta and sin 2 theta similarly
OpenStudy (aravindg):
infact once you get any of the above you can use tan theta to get value of other
OpenStudy (anonymous):
and then divide by 2 ?
OpenStudy (anonymous):
use formula for cos2theta and sin2theta and divide by 2 ? to get half angle?
OpenStudy (anonymous):
sin2θ = 2cosθsinθ
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OpenStudy (aravindg):
oops i think i made a mistake on that
OpenStudy (aravindg):
use this then
1+cos 2 theta =2cos ^2 theta
OpenStudy (aravindg):
here 2 theta =45
OpenStudy (aravindg):
theta =2.5
OpenStudy (aravindg):
*22.5