solve the equation analytically.
\[4^{2x}=\frac{ 1 }{ 2 }\]
\[2xlog4=\log \frac{ 1 }{ 2 }\]
what can i do next in orfer to solve for the x dont i need a base
the base is already 10 by default
actually by default, it can either be "e" or "10" generally, we take "e" if nothing is mentioned.
\[4^{2x} =\frac{ 1 }{ 2 }\]You could do this:\[\ln(4^{2x})=\ln(\frac{ 1 }{ 2 }) \rightarrow 2xln(4)=\ln(\frac{ 1 }{ 2 }) \rightarrow 2x=\frac{ \ln \frac{ 1 }{ 2 } }{ \ln(4) }\]\[x=2(\frac{ \ln \frac{ 1 }{ 2 } }{ \ln(4) })\]
well, the question doesn't have logs given to us in the first place. so its our choice to take whatever base we want to of the log base 2 would be ideal here.
@Lynncake the answer equals to \[x=-\frac{ 1 }{ 4 }\] i see whereyou got the 1/4 but how can i pull the negative
got it....
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