Solve the system of equations algebraically. I know i have to change one of these equations to y = mx + b: 2x - y = 6 and -3x + 4y = 1. I just don't know what to do from there.
do you know how to solve to equation by y ?
what do you mean?
oh wait. i think i know how to do this. do you change the -3x + 4y = 1 to y = mx + b? And then solve for y?
thats how you solve for y it is when you change it into y = mx + b you want to know what "y" so you are trying to " solve for it" this goes the same as any other variable
don't you need to solve for x too?
yes you do it says "solve a system of equations" and you are given x y 2x - y = 6 -3x + 4y = 1. I
only 2 :D
first of all put them in slope intercept form
i did, but i didn't get some clean numbers like integers.
fractions
but you know how to solve systems of equations right?
just sub them back in and see if the are correct
for fractions just get the reciprocal
and try to take them out
Is slope intercept form the only way to go through it? Can you leave them as the orinal ones and get rid of y by multiplying all of the numbers by 4 for 2x - y = 24?
then solve for x
solving by graphing
i believe i am solving the equations algrebraically. But i am not sure what you mean by graphing...
graphing them and see where they intersect (not the advisable method)
and there also elimination method
well another check is by subbing the x and y values and see if it works
slope intercept is not a way or method it is how the equation must be lined up before any calculations take place
if they are all put in slope intercept form it should look like this y = 2 x - 6 y = 3x/4 + 1.1/4
does that look ok? :/
if i were to use elimination method because you to cancel and "eliminate" one of the terms distributive property is extensively used here multiply -3 [ ( 2 x ) - 6 = y ] multiply 8 [ (3x/4 ) + 1.1/4 = y ]
until get the solution for y then substitute it to get x
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