1. Solve by completing the square 4r^2 - 28r = -9 2. Use the discriminant to find the number of unique real solutions. 3. Solve with the quadratic formula.
wat did u get for number 1?
I didn't solve it, not sure how.
well first we rearrange the formula to get 4r^2 - 28r = -9 4r^2 - 28r + 9 = 0 and from here u factorize the equation
do u know how to factorize an equation or do u want me to teach u how?
not sure how, please teach me. I'm horrible with math
ok ill do it and ill explan wat i did after i finish
Alright, thank you. I appreciate it.
4r^2 - 28r + 9 = 0 4(r^2 - 7r) +9 \[4(r - \frac{ 7 }{ 2 })^{2} + 9 - 4(\frac{ 7 }{ 2 })^{2}\] \[4(r - \frac{ 7 }{ 2 })^{2} + 9 - 4(\frac{ 49 }{ 4 })\] \[4(r - \frac{ 7 }{ 2 })^{2} + 9 - 49 \] \[4(r - \frac{ 7 }{ 2 })^{2} - 40\]
ok i need u to be here and focus, u there?
Yes.
sry im back my internet was giving trouble, u there again?
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