Question

3cosx+1=2secx

Answer 1

This a solve one? Looks like it. If so, set to 0, factor, solve the factors. That would be the basics of it.

Answer 2

Okay, thanks

Answer 3

start with

\[3\cos(x) + 1 = \frac{2}{\cos(x)}\]

multiply each term by cos(x)

\[3\cos^2(x) + \cos(x) = 2.... or.... 3\cos^2(x) + \cos(x) - 2 = 0\]

you now have a quadratic equation that can be factorised.

hope this helps