Question

The picture shows a box sliding down a ramp.
http://oi49.tinypic.com/35bfthx.jpg

What is the distance, in feet, that the box has to travel to move from point A to point C?

A)10/cot 62
B)1O cosec62
C)10/sec62
D)10 sin 62

Answer 1

@terenzreignz @Rav

Answer 2

Basically this is saying find the length of AC, the hypotenuse. So let's apply SOHCAHTOA: you want the H on top of a fraction, so you want either 1/sin (csc) or 1/cos (sec). But the only angle you know is <ACB which is opposite from the known side. So you want csc, because sec = H/O. Then O = 10 and:

(sec 62) = H/10
H = 10 csc 62

Answer 3

oh ok,thank you! do u know the answer to this? When an altitude is drawn to the hypotenuse of a right triangle, the lengths of the segments of the hypotenuse are 4 and 9. What is the length of the altitude?

9

13

4

6

Answer 4

@Rav

Answer 5

Working on it sorry for the long wait... give me 5 more mins.

Answer 6

its ok

Answer 7

By constructing an altitude you are creating 2 right triangles. Hence use Pythagorean theorem:

x^2 + y^2 = c+2 where c = hypotenuse, x = a side, y = a side, and let z = the length of the altitude.

For simplicity x^2 = X, y^2 = Y, z^2 = Z

Then
X + Y = 169
Z + 81 = Y
Z + 16 = X

Then
X + 81 + Z = 169
X = Z + 16
Z + 16 + 81 + Z = 169
2Z + 97 = 169
2Z = 72
Z = 36
Z = z^2 remember, so:
z = sqrt(36) = 6.

Answer 8

Ta-da.

Answer 9

oh thanks bro,do u know this one? Two quadrilaterals EFGH and IJKL are drawn on a coordinate grid. The coordinates of the vertices of each quadrilateral are given below.

EFGH – E (1, 4), F (2, 4), G (2, 2), H (1, 2)
IJKL – I (-4, -1), J (-1, -1), K(-1, -7), L(-4, -7)

Which statement about the two quadrilaterals is true?

The side lengths of IJKL are three times the corresponding side lengths of EFGH.

The side lengths of IJKL are congruent to the corresponding side lengths of EFGH.

The side lengths of IJKL are not proportional to the corresponding side lengths of EFGH.

The side lengths of IJKL are half of the corresponding side lengths of EFGH.
@Rav

Answer 10

I hope there's a picture with that. All this mental graphing is tough.

Answer 11

there isnt :( if you dont want to do it its ok lol @Rav i really aprreciate your help

Answer 12

i think its C @Rav

Answer 13

C is not the answer.

Answer 14

B is the answer. The side lengths of IJKL are three times the corresponding side lengths of EFGH.

Answer 15

can u just do this one? The figure below shows some steps that Meg used to construct an angle bisector BO of an angle ABC.
http://oi47.tinypic.com/28tkv8x.jpg
In the next step Meg draws two arcs, one from point P and the other from point Q. Which of the following is true for this step?

The width of the compass is not the same while drawing the arcs from point P and point Q.

The width of the compass is adjusted to BQ to draw the arc from point P and BA to draw an arc from Q.

The width of the compass is the same while drawing the arcs from point P and point Q.

The width of the compass is adjusted to BC to draw the arc from point P and BP to draw an arc from Q. The other one im fine with i got the answer

Answer 16

oh thank you lol @Rav

Answer 17

Brain had a bad moment I meant A is the answer. 5 AM and I'm not asleep, something wrong with me lol.

Answer 18

lol i know can u do this one? and then lets both go to sleep lol its late @Rav

Answer 19

and its A then?

Answer 20

A for the question about IJKL and EFGH, yes. As I said before "The side lengths of IJKL are three times the corresponding side lengths of EFGH."

Answer 21

Here's a graph: http://www.wolframalpha.com/input/?i=%281%2C+4%29%2C%282%2C+4%29%2C%282%2C+2%29%2C%281%2C+2%29%2C%28-4%2C+-1%29%2C%28-1%2C+-1%29%2C%28-1%2C+-7%29%2C%28-4%2C+-7%29++

Answer 22

For the last one the compass should not be changed when drawing the arc from P to Q. The compass' radius should remain constant when drawing the arc otherwise you won't properly bisect the angle, assuming of course that P and Q are equidistant from B.

Answer 23

so whats the answer? @Rav

Answer 24

C. The width of the compass is the same while drawing the arcs from point P and point Q.

Answer 25

thanks bro. i swear just one more can u answer for me? PLEASE :( last one im supper tirred lol @Rav

Answer 26

The picture shows a portion of an irrigation system for a farm. QR is the main water pipe.
http://oi49.tinypic.com/mwvcbm.jpg

What is the length of the water pipe PR?

10 feet

20 feet

14.1 feet

28.3 feet


Two end points of a line segment are (-12, -2) and (-6, -10). What are the coordinates of the point on the line through which its bisector passes?

(-18, -12)

(-9, -6)

(-7, -8)

(-11, -4)

Answer 27

these 2 thats it. @Rav