Question

Please help me!!!
If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? (The specific heat of aluminum is 0.90 J/(g × °C).)

0.10 g

10.0 g

12.0 g

57.7 g

Answer 1

Q= M *S *delta T
M=Q /S*Delta T
find the M
Q is in joules energy
S is specific heat capacity and delta T is temperature differeence

Answer 2

So the answer is..?

Answer 3

u tell me i will tell its right or nooo:)
cant u solve the above equation

Answer 4

..Cannnttt u?

Answer 5

i cannn but u have to learn right :)

Answer 6

Bla.. nvm

Answer 7

M= 832 / 0.9*77
tell me the answer common

Answer 8

c

Answer 9

yaaa 12 g:)

Answer 10

Thank u!!