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Find the volume of the solid of revolution generated by revolving the equation \(y=\sqrt(x)\) about the line x=4 (The region is bounded by the x axis and x=4)
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I understand if I rewrite the equation as y=\(\sqrt{x-4}\) then integrate with appropriate bounds it will work, but there is some sort of alternate interpretation I am not understanding.
*rewrite the equation as y=\(\sqrt{x+4}\)
|dw:1365190324765:dw| \[\int 2\pi ~r~h\]
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