Question

write the equation of the quadratic function with roots 0 and 1 and a vertex at (1/2, -2/3).

Answer 1

y = a(x - 0) * (x - 1)
If x = 1/2 and y = -2/3
-2/3 = a*(1/2)*(1-(1/2)
a = -8/3
y = (-8/3) * (x^2-x)
y = /8/3x^2 - -8/3x

can someone tell me if this is correct

Answer 2

It should read y = -8/3x^2 -8/3x

Answer 3

This is correct except you need to continue simplifying:

y = -8/3x^2 -8/3x

y(3x^2-3x) = -16
3y(x^2 - 1) = -16
y = -16/(3(x-1)(x+1))