Question

Find the critical point
f(x)=5x^2+3x-4

Answer 1

@MATTW20

Answer 2

the derivate is 10x+3

Answer 3

set that equal to 0 and solve for x

Answer 4

got it?

Answer 5

no :(

Answer 6

10x+3=0
just solve for x. it's basic algebra

Answer 7

o i thought u meant the first equation :)

Answer 8

-3/10

Answer 9

that's your critical point

Answer 10

WOw that was easy

Answer 11

yup lol

Answer 12

i feel dumb lol

Answer 13

Ok i have one more question...

Answer 14

No you shouldn't you'll get it. I'm in calc 1 as well. But we finished this section a little while ago you'll get it

Answer 15

im honors pre cal...it sucks

Answer 16

wow thats advanced pre-calc

Answer 17

OK Last Question:

A stone is launched vertically upward from a cliff 32ft above the ground at a speed of 16ft/s. Its height above the ground t seconds after the launch is given by s=-16t^(2)+16t+32 for 0<_t<_2

Answer 18

find the critical point

Answer 19

find the derivative first thought right?

Answer 20

yes that is the first step in finding the critical point

Answer 21

-1/2?

Answer 22

critical point not the derivative

Answer 23

just 1/2

Answer 24

So the stone reaches its maximum height at 1/2 second

Answer 25

yes in this case it does. but you generally have to check you start and endpoints because they can be your min or max as well. but in this case they aren't

Answer 26

Thank you so much for your help tonight.

Answer 27

no problem. you're a quick learner I have spent more time helping people with a single algebra 1 question than I spent helping you all night.

Answer 28

awww ur sweet!! I hate calculus now lol

Answer 29

lol