Question

lim x-> infiniti tanhx

Answer 1

how's tanh x defined ?

Answer 2

\[\lim_{x \rightarrow \infty} tanhx\]

Answer 3

\[\frac{ sinhx }{ coshx }\]

Answer 4

in terms of powers of 'e' ?

Answer 5

yup

Answer 6

what will it be ?

Answer 7

hun?

Answer 8

ok, tanh x = [e^x-e^(-x)]/ [e^x+e^(-x)]
right ?
i meant that

Answer 9

exactly

Answer 10

now, you can write e^x as 1/e^(-x)
substitute this and simplify....

Answer 11

I didn't understand how u did that?

Answer 12

\(\huge x^n= \dfrac{1}{x^{-n}}\)

Answer 13

didn't you know that ?

Answer 14

hehe nope

Answer 15

now you know :)
can you simplify ?

Answer 16

u cancel out then right?

Answer 17

do it and show me what you meant

Answer 18

I thought x^-1 = 1/x

Answer 19

that is also true!

Answer 20

arg I think I just confused myself nevermind

Answer 21

what i asked you to do is,
\(\huge \dfrac{1/e^{-x}-e^{-x}}{1/e^{-x}+e^{-x}}\)
got this ?
can you simplify this a bit ?

Answer 22

yes so its -1/1 right?

Answer 23

omg no nevermind

Answer 24

right for first half?