Question

how to transform ln((e^8-1)/(e^4-1)) to ln(e^4+1)

Answer 1

e^8-1 can be written as (e^4-1)(e^4+1)

Answer 2

\[\ln(\frac{ e ^{8}-1 }{ e ^{4}-1 })\]

Answer 3

is that how it is supposed to be ???

Answer 4

^ I assumed the same, too.

Answer 5

okay...thank you...