square root 8 over square root 3
I thought it was 2 square root 2 over square root 3 but I must have done the order of operations wrong
how can you rewriting 8 using power of 2 ?
Sorry I wrote the problem wrong. Correct now.
how is it ?
My book says the answer is +/- 2 square root 6 over 3.
yes is right your book
because 8 = 2^2 *2 yes ?
but sqrt(2^2) = +/- 2 yes ?
That is what I got too, once I redid it with the right number.
I'm solving 3x squared = 8 using the square root property. Reduced it to x square = 8/3.
3x^2 =8 x^2 = 8/3 x_1,2 = +/- sqrt (8/3)
on this way ?
Yes, that's my understanding of how to solve for x. But book says otherwise.
but sqrt8 = 2sqrt2
That's what I thought. I'll ask instructor next class period. thanks for your help.
than will be +/- 2sqrt2 /sqrt3 = +/- 2sqrt6 / 3 so this you will get after ratzionlized the denominator ok ?
so than your book is right sure
Oh cause you can't leave a square root on the bottom equation if I'm remembering correctly. That's a step I forgot.
yes when there is on denominator an radical you need ratzionaliz the denominator and in this way will be eliminated the radical from there ok ?
Got it. Thanks
yw good luck bye
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