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how to solve using the quadratic formula d^2-4d+1=0
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find two numbers whose sum = "-4" product = "+1"
we cant.. so, we use the quadratic formula
comparing with ax^2 +bx+c-0 sum of roots =-b/a =4 product of roots are c/a=1 hence roots are 1/4 and 4
\[d=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
comparing with ax^2 +bx+c-0 sum of roots =-b/a =4 product of roots are c/a=1 hence roots are 1/4 and 4/2
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d(approximately equals)3.7321,0.2679
\[d ^{2}-4d+1=0\] a=1 b=-4 c=1 Plug these into the quadratic formula. See electrokid's post for the formula.
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