The IVT is often used to verify that a function has a zero. For the following graph what would be the proper way to state the IVT theorem to show that there is a zero in the range?

A. f(x) is continuous on [-2, 2] and let k be zero. Then there exists a number c inside the interval such that, f(c) = k.
B. f(x) is continuous on [-5, 5] and let k be zero. Then there exists a number c inside the interval such that, f(c) = k.
C. f(x) is continuous on [-2, 5] and let k be zero. Then there exists a number c inside the interval such that, f(c) = k.
D. f(x) is continuous on [4, 5] and let k be zero. Then there exists a number c inside the interval such that, f(c) = k.

Question

The IVT is often used to verify that a function has a zero. For the following graph what would be the proper way to state the IVT theorem to show that there is a zero in the range?

A.	f(x) is continuous on [-2, 2] and let k be zero. Then there exists a number c inside the interval such that, f(c) = k.
	B.	f(x) is continuous on [-5, 5] and let k be zero. Then there exists a number c  inside the interval such that, f(c) = k.
	C.	f(x) is continuous on [-2, 5] and let k be zero. Then there exists a number c  inside the interval such that, f(c) = k.
	D.	f(x) is continuous on [4, 5] and let k be zero. Then there exists a number c  inside the interval such that, f(c) = k.

anonymous · Answer

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anonymous · Answer

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