Question

How would you graph r = -2sec( Θ - 11π/6 ) ?

Answer 1

Well, let's first look at what the sec graph looks like and see each of the components.

Answer 2

is -2 the radius?

Answer 3

F(t) = Af(Bt – C) + D
where
A: amplitude is A
B: period is (2π)/|B|
C: phase shift is C/B
D: vertical shift is D

Answer 4

-2 is the amplitude, ie how much the graph goes up and down.

Answer 5

r = secΘ is a line

Answer 6

Trig function, right?
I'm sort of confused about what you mean, but here is a site explaining how to get to the sec graph from cos. You then apply the components like amp, period, etc, to get the resultant.

Answer 7

heh, poler equation

Answer 8

polar*