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Mathematics 14 Online
OpenStudy (anonymous):

what are (+infinity) and(-infinity)? are they integers?

jimthompson5910 (jim_thompson5910):

they are not integers, but I think they are part of the extended real number set

OpenStudy (compassionate):

Infinity is all numbers. e.g: 1/3, 1.2, square root of 3, 100, etc.

OpenStudy (anonymous):

+infinity means "bigger than you can ever imagine", -infinity means "smaller than a smallest number." they are not integers, it is more like a limit.

OpenStudy (anonymous):

what is fermat's last theorem?

terenzreignz (terenzreignz):

Be careful what you wish for, @ParthKohli Take \[n=2\]\[a=3\]\[b=4\]\[c=5\] I think you mean \[\huge \color{red}{n>2}\]

terenzreignz (terenzreignz):

And even if you had n > 2 What if b = 0 and c = a hahaha :P

terenzreignz (terenzreignz):

Sometimes, I feel like you do this stuff on purpose.... Fermat's last theorem... no positive integers a,b, and c would satisfy \[\huge a^n + b^n = c^n\] if n is an integer greater than 2.

terenzreignz (terenzreignz):

positive integers, parthkohli

OpenStudy (anonymous):

for n>2 what would be the method to write a ,b and c?

terenzreignz (terenzreignz):

I'm not sure I follow, @rahulon

OpenStudy (anonymous):

suppose there is a problem in which someone has to solve the eqn. x+y=z for x,y and z how that someone will solve it ?

terenzreignz (terenzreignz):

Normally, I suppose... it's just that for \[a^n + b^n = c^n\] There would be no integer solution for a,b, and c, for any positive integer n > 2 But there will be solutions.

OpenStudy (anonymous):

for n=1 only

OpenStudy (anonymous):

find x,y and z

OpenStudy (anonymous):

i mean a,b and c

terenzreignz (terenzreignz):

Well, it's just a linear equation then?

OpenStudy (anonymous):

then is it easy to find out a,b and separately ?

terenzreignz (terenzreignz):

I would think so.

OpenStudy (anonymous):

would u like to give that formula to find out a,b and c separately

terenzreignz (terenzreignz):

Formula when a + b = c?

OpenStudy (anonymous):

a+b=c

OpenStudy (anonymous):

jk i dont even know..

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